(x-5)/(x^2-7x+10)=0

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Solution for (x-5)/(x^2-7x+10)=0 equation:


D( x )

x^2-(7*x)+10 = 0

x^2-(7*x)+10 = 0

x^2-(7*x)+10 = 0

x^2-7*x+10 = 0

x^2-7*x+10 = 0

DELTA = (-7)^2-(1*4*10)

DELTA = 9

DELTA > 0

x = (9^(1/2)+7)/(1*2) or x = (7-9^(1/2))/(1*2)

x = 5 or x = 2

x in (-oo:2) U (2:5) U (5:+oo)

(x-5)/(x^2-(7*x)+10) = 0

(x-5)/(x^2-7*x+10) = 0

x^2-7*x+10 = 0

x^2-7*x+10 = 0

DELTA = (-7)^2-(1*4*10)

DELTA = 9

DELTA > 0

x = (9^(1/2)+7)/(1*2) or x = (7-9^(1/2))/(1*2)

x = 5 or x = 2

(x-2)*(x-5) = 0

(x-5)/((x-2)*(x-5)) = 0

x-5 = 0 // + 5

x = 5

x in { 5}

x belongs to the empty set

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